| Date 08/09/2010 |
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| Script S3_2_7.m | |||
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%A quartz prism %============================================== % %refractive indices of quartz %for lambda = 0.5893 ne=1.5543; no=1.5443; %legs of the right triangle AB=1; CB=3; %the vertex alfa1 (see Fig. 3.23) alfa1=atan(AB/CB); alfa1g=alfa1*180/pi %the angles of refraction on surface AC %for the ordinary and extraordinary rays arge=ne*sin(alfa1); argo=no*sin(alfa1); alfa2e=asin(arge)*180/pi alfa2o=asin(argo)*180/pi %calculus of the segment t t=(CB/2)*sin(alfa1) %calculus of the phases lambda=0.5893; fio=(2*pi/lambda)*no*t fiog=fio*180/pi fie=(2*pi/lambda)*ne*t fieg=fie*180/pi %phases in the range 0°-360° fiogrem=rem(fiog,360) fiegrem=rem(fieg,360) diffg=fiegrem-fiogrem %phases difference difffase=diffg*pi/180 %lambda difference difflambda=difffase*lambda/(2*pi) %============================================== % |
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